四大文化赛道完整展开
06-deliverables/appendix-code.md
民族展馆导览:最短参观路径搜索 代码附录
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文件类型Markdown
10-cases/s4-jh-07-hall-navigation/06-deliverables/appendix-code.md
- 完整解题档案:complete-solution-dossier.md
Python 主实现
源文件:main.py
- 实现状态:当前已有可执行实现
from collections import deque
import sys
def solve(data: str) -> str:
raw_lines = [line.rstrip() for line in data.splitlines() if line.strip()]
if not raw_lines:
return ""
rows, cols = map(int, raw_lines[0].split())
grid = raw_lines[1:1 + rows]
start = (-1, -1)
target = (-1, -1)
for row in range(rows):
for col in range(cols):
if grid[row][col] == "S":
start = (row, col)
elif grid[row][col] == "T":
target = (row, col)
directions = ((1, 0, "D"), (0, -1, "L"), (0, 1, "R"), (-1, 0, "U"))
queue = deque([start])
visited = [[False] * cols for _ in range(rows)]
parent = [[None] * cols for _ in range(rows)]
visited[start[0]][start[1]] = True
while queue:
row, col = queue.popleft()
if (row, col) == target:
break
for dr, dc, mark in directions:
nxt_row = row + dr
nxt_col = col + dc
if not (0 <= nxt_row < rows and 0 <= nxt_col < cols):
continue
if visited[nxt_row][nxt_col] or grid[nxt_row][nxt_col] == "#":
continue
visited[nxt_row][nxt_col] = True
parent[nxt_row][nxt_col] = (row, col, mark)
queue.append((nxt_row, nxt_col))
if not visited[target[0]][target[1]]:
return "distance=-1\npath=NONE"
path = []
cur = target
while cur != start:
row, col = cur
prev_row, prev_col, mark = parent[row][col]
path.append(mark)
cur = (prev_row, prev_col)
path.reverse()
return f"distance={len(path)}\npath={''.join(path)}"
if __name__ == "__main__":
sys.stdout.write(solve(sys.stdin.read()).strip())
sys.stdout.write("\n")
C++ 对照实现
源文件:main.cpp
- 实现状态:当前已有可执行实现
#include <algorithm>
#include <deque>
#include <iostream>
#include <string>
#include <tuple>
#include <vector>
using namespace std;
int main() {
ios::sync_with_stdio(false);
cin.tie(nullptr);
int rows, cols;
if (!(cin >> rows >> cols)) {
return 0;
}
vector<string> grid(rows);
pair<int, int> start = {-1, -1};
pair<int, int> target = {-1, -1};
for (int row = 0; row < rows; ++row) {
cin >> grid[row];
for (int col = 0; col < cols; ++col) {
if (grid[row][col] == 'S') {
start = {row, col};
} else if (grid[row][col] == 'T') {
target = {row, col};
}
}
}
const int dr[4] = {1, 0, 0, -1};
const int dc[4] = {0, -1, 1, 0};
const char mark[4] = {'D', 'L', 'R', 'U'};
deque<pair<int, int>> queue;
vector<vector<int>> visited(rows, vector<int>(cols, 0));
vector<vector<tuple<int, int, char>>> parent(rows, vector<tuple<int, int, char>>(cols, {-1, -1, '?'}));
queue.push_back(start);
visited[start.first][start.second] = 1;
while (!queue.empty()) {
auto [row, col] = queue.front();
queue.pop_front();
if (make_pair(row, col) == target) {
break;
}
for (int dir = 0; dir < 4; ++dir) {
int nxt_row = row + dr[dir];
int nxt_col = col + dc[dir];
if (nxt_row < 0 || nxt_row >= rows || nxt_col < 0 || nxt_col >= cols) {
continue;
}
if (visited[nxt_row][nxt_col] || grid[nxt_row][nxt_col] == '#') {
continue;
}
visited[nxt_row][nxt_col] = 1;
parent[nxt_row][nxt_col] = {row, col, mark[dir]};
queue.push_back({nxt_row, nxt_col});
}
}
if (!visited[target.first][target.second]) {
cout << "distance=-1\n";
cout << "path=NONE\n";
return 0;
}
string path;
pair<int, int> cur = target;
while (cur != start) {
auto [prev_row, prev_col, step] = parent[cur.first][cur.second];
path.push_back(step);
cur = {prev_row, prev_col};
}
reverse(path.begin(), path.end());
cout << "distance=" << path.size() << "\n";
cout << "path=" << path << "\n";
return 0;
}